Book: RS Aggarwal - Mathematics
Chapter: 4. Inverse Trigonometric Functions
Subject: Maths - Class 12th
Q. No. 2 of Exercise 4C
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2
Prove that:
To Prove: 
Formula Used: sin 2A = 2 × sin A × cos A
Proof:
LHS 
… (1)
Let x = sin A … (2)
Substituting (2) in (1),
LHS 
= sin-1 (2 × sin A × cos A)
= sin-1 (sin 2A)
= 2A
From (2), A = sin-1 x,
2A = 2 sin-1 x
= RHS
Therefore, LHS = RHS
Hence proved.
Chapter Exercises
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