Solve for x:
To find: value of x
Given:
LHS = cos(sin-1 x) … (1)
Let sin θ = x
Therefore θ = sin-1 x … (2)
From the figure,
… (3)
From (2) and (3),
… (4)
Substituting (4) in (1), we get
LHS
Therefore,
Squaring and simplifying,
⇒ 81 – 81x2 = 1
⇒ 81x2 = 80
Therefore, are the required values of x.