Solve for x:

To find: value of x

Formula Used:

Given:

LHS = cos(2sin^{-1} x)

Let θ = sin^{-1} x

So, x = sin θ … (1)

LHS = cos(2θ)

= 1 – 2sin^{2} θ

Substituting in the given equation,

Substituting in (1),

Therefore, are the required values of x.

1