Book: RS Aggarwal - Mathematics
Chapter: 4. Inverse Trigonometric Functions
Subject: Maths - Class 12th
Q. No. 11 of Objective Questions
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11
Mark the tick against the correct answer in the following:
The value of 
is
To Find: The value of 
Now, let x =
sin x =sin (
)
Here range of principle value of sine is [-
]
x = 
[-
]
Hence for all values of x in range [-
] ,the value of
is
sin x =sin (
) (
sin (
)= sin (
) )
sin x =sin (
) (
sin (
)= sin 
as here 
)
x = 
