Mark the tick against the correct answer in the following:
The value of
is
To Find: The value of ![]()
Now, let x =![]()
sec x =sec (
)
Here range of principle value of sec is [0,
]
x =
[0,
]
Hence for all values of x in range [0,
] ,the value of
is
sec x =sec (2
) (
sec (
)= sec (
) )
sec x =sec (
) (
sec (
)= sec
)
x = ![]()