Without expanding the determinant, prove that

SINGULAR MATRIX A square matrix A is said to be singular if |A| = 0.


Also, A is called non singular if |A| ≠ 0.


We know that C1 C1-C2, would not change anything for the determinant.

Applying the same in above determinant, we get


Now it can clearly be seen that C1=8 × C3


Applying above equation we get,



We know that if a row or column of a determinant is 0. Then it is singular determinant.


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