Given : and

Matrix A is of order 2 2, Matrix B is of order 2 2

To find : 3A² – 2B + I

Formula used :

Where c_ij = a_i1b_1j + a_i2b_2j + a_i3b_3j + ……………… + a_inb_nj

If A is a matrix of order a b and B is a matrix of order c d ,then matrix AB exists and is of order a d ,if and only if b = c

A² = = =

A² =

3A² = 3 × =

3A² =

2B = 2 × =

2B =

I =

3A² – 2B + I = + =

3A² – 2B + I =

3A² – 2B + I =