Using properties of determinants prove that:
[R1’ = R1 - R2 & R2’ = R2 - R3]
[R1’ = R1 - R2]
[R2’ = R2*2]
[R2’ = R2 + R3]
= (1/2)[0 + 3(1 + q) - (1 + 6p + 3q) + p(6 + 3p - 3p)] [expansion by first row]
= (1/2)(3 + 3q - 1 - 6p - 3q + 6p) = 1
1
Using properties of determinants prove that:
[R1’ = R1 - R2 & R2’ = R2 - R3]
[R1’ = R1 - R2]
[R2’ = R2*2]
[R2’ = R2 + R3]
= (1/2)[0 + 3(1 + q) - (1 + 6p + 3q) + p(6 + 3p - 3p)] [expansion by first row]
= (1/2)(3 + 3q - 1 - 6p - 3q + 6p) = 1