Using properties of determinants prove that:
[R1’ = R1 + R2 + R3]
[R1’ = R1/3(x + y)]
[R2’ = R2 - R3]
[R2’ = R2/y]
[R1’ = R1 - R2]
= 3y(x + y)[0 + 3(x + y) - x + 0] [expansion by first row]
= 3y(x + y)(3y) = 9y2(x + y)