Using properties of determinants prove that:



[R1’ = R1 + R2 + R3]


[R1’ = R1/3(x + y)]


[R2’ = R2 - R3]


[R2’ = R2/y]


[R1’ = R1 - R2]


= 3y(x + y)[0 + 3(x + y) - x + 0] [expansion by first row]


= 3y(x + y)(3y) = 9y2(x + y)


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