Using properties of determinants prove that:
[C1’ = C1/x, C2’ = C2/y & C3’ = C3/z]
[C1’ = C1 - C2 & C2’ = C2 - C3]
[C1’ = C1/(x - y)& C2’ = C2/(y - z)]
= xyz(x - y)(y - z)(0 + 0 + y + z - x - y) [expansion by first row]
= xyz(x - y)(y - z)( z - x)