Using properties of determinants prove that:



[R1’ = R1 + R2 + R3]


[R1’ = R1/(a + b + c)]


= (a + b + c)[2(b - c)c - b(c - a) + (c + a)(c - a) - (a + b)(b - c)] [expansion by first row]


= (a + b + c)(2bc - 2c2 - bc + ab + c2 - a2 - ab - b2 + ac + bc


= (a + b + c)(ab + bc + ac - a2 - b2 - c2)


= 3abc - a3 - b3 - c3


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