Without expanding the determinant, prove that:
Operating R1→R1-R2, R2→R2-R3
→
→
Taking (a-b) and (b-c) from R1, R2
→
Method 1:
For the two determinants to be equal, their difference must be 0.
Since 2 columns have only 0 as their elements, by properties of determinants
=0
Method 2:
Expanding both with C1
LHS
=(a-b)(b-c)(-a+c)
RHS
=(a-b)(b-c)(b+c-a-b)
=(a-b)(b-c)(-a+c)
∴ LHS = RHS