Mark the tick against the correct answer in the following:
To find: Value of
We have,
⇒
Taking 2 common from R2
Taking 6 common from R3
Applying
Expanding column 1
⇒ 12 [1{(1)(14)-(6)(2)}]
⇒ 12 [1{(14)-(12)}]
⇒ 12[2]
⇒ 24