Mark the tick against the correct answer in the following:
To find: Value of 
We have, 
Applying 
⇒ 
Applying 
⇒ 
Applying 
⇒ 
Applying 
⇒ 
Expanding along R2
⇒ 
[x{(2x)(8x) - (8x+8y)(0)}]
⇒ 
[x{16x2}]
⇒ x3
1
Mark the tick against the correct answer in the following:
To find: Value of
We have,
Applying
⇒
Applying
⇒
Applying
⇒
Applying
⇒
Expanding along R2
⇒ [x{(2x)(8x) - (8x+8y)(0)}]
⇒ [x{16x2}]
⇒ x3