Mark the tick against the correct answer in the following:
To find: Value of
We have,
Applying +
⇒
⇒
⇒ (a+b+c)
Expanding along R1
⇒ (a+b+c)[2{(c) (c) – (b) (a)} -1{(c+a)(c)-(a+b)(a)} + 1{(c+a)(b)-(a+b)(c)}]
⇒ (a+b+c)[2{c2 – ab} -1{c2+ac-a2-ab} + 1{bc+ba-ac-bc}]
⇒ (a+b+c)[2c2 – 2ab - c2 – ac + a2 + ab + ba - ac]
⇒ (a+b+c)[c2 + a2 - 2ac]
⇒ (a+b+c)(c – a)2