To find: Value of

We have,

Applying

⇒

⇒

Taking (b – a) common

⇒

Applying

⇒

⇒

Taking (c - b) common

⇒

Expanding along C₃

⇒ (b – a) (c – b) [1{(c) (1) – (a) (1)}]

⇒ (b – a) (c – b) (c – a)

⇒ (a – b) (b – c) (c – a)