To find: Value of

We have,

Applying

⇒

Taking 2 common

⇒

Applying

⇒

Expanding along R₁

⇒ 2 [c{(c + a) (a + b) – (b) (c)} + a{(b)(c) – (c) (c + a)}]

⇒ 2 [c{(ac + cb +a² + ab – bc} + a{(bc – c² - ac)}]

⇒ 2 [c{(ac + a² + ab)} + a{(bc – c² - ac)}]

⇒ 2 [ac² + ca² + abc + abc – ac² – a²c]

⇒ 2 [2abc]

⇒ 4abc