Mark the tick against the correct answer in the following:
To find: Value of 
We have, 
Applying 
⇒ 
Applying 
⇒ 
Expanding along R1
⇒ [2{(5)(x+14) – (6)(x+10)} – 3{(4)(x+14) – (6)(x+7)} + 4 {(4)(x+10) – (5)(x+7)}]
⇒ [2{5x + 70 – 6x – 60} – 3{4x + 56 -6x - 42} + 4 {4x + 40 – 5x - 35}]
⇒ [2{10 - x} – 3{14 -2x} + 4 {5 - x}]
⇒ [20 – 2x – 42 + 6x + 20 - 4x]
⇒ -2
1