Mark the tick against the correct answer in the following:

The solution set of the equation is


To find: Value of x


We have,


Applying



Applying



Expanding along R1


[(2x-7){(x)(x) – (6)(2)} + (14-x){(2)(6) – (x)(7)] = 0


[(2x-7){x2– 12} + (14-x){12 – 7x}] = 0


[2x3 – 24x – 7x2 + 84 + 168 – 98x -12x + 7x2] = 0


[2x3 – 134x + 252] = 0


[x3 – 67x + 126] = 0


By Hit and trial x = -2, 3, -7

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