Mark the tick against the correct answer in the following:
The solution set of the equation 
is
To find: Value of x
We have, 
Applying 
⇒ 
Applying 
⇒ 
Expanding along R1
⇒ (3x-11){(3x-11)(3x-8) – (3)(11-3x)} – (11-3x){(0)((3x-8) – (11-3x)(3)} = 0
⇒ (3x-11){(3x-11)(3x-8+3)} – (11-3x){–(11-3x)(3)} = 0
⇒ (3x-11)2(3x-5)} + (3x-11){(3x-11)(3)} = 0
⇒ (3x-11)2(3x-5)} + (3x-11)2(3)} = 0
⇒ (3x-11)2(3x-5+3) = 0
⇒ (3x-11)2(3x-2) = 0
⇒ 
1