Find the value of k for which the
points P(5, 5), Q(k, 1) and R(11, 7) are collinear.


Since they are collinear, the area will be 0


→


Expanding with C3


→ 0 = (7k-11)-(35-55)+(5-5k)


→ 0= 2k-14


→ 2k=14


∴ k=7


1