Let ƒ(x) =

Show that ƒ(x) is continuous but not differentiable at x=1


Left hand limit at x = 1



f(x) = x is polynomial function and a polynomial function is continuous everywhere


Right hand limit at x = 1



f(x) = 2 - x is polynomial function and a polynomial function is continuous everywhere


Also, f(1) =1


As we can see that,



Therefore,


f(x) is continuous at x =1


Now,


LHD at x = 1



RHD at x = 1




As, LHD ≠ RHD


Therefore,


f(x) is not differentiable at x = 1


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