Let ƒ(x) =
Show that ƒ(x) is continuous but not differentiable at x=1
Left hand limit at x = 1
f(x) = x is polynomial function and a polynomial function is continuous everywhere
Right hand limit at x = 1
f(x) = 2 - x is polynomial function and a polynomial function is continuous everywhere
Also, f(1) =1
As we can see that,
Therefore,
f(x) is continuous at x =1
Now,
LHD at x = 1
RHD at x = 1
As, LHD ≠ RHD
Therefore,
f(x) is not differentiable at x = 1