If ƒ(x) = |x| show that ƒ’(2)=1
Given function is f(x) = |x|
LHD at x = 2:
RHD at x = 2:
As, LHD = RHD
Therefore, f(x) = |x| is differentiable at x = 2
Now f’(2) =
Therefore,
f’(2) = 1