If ƒ(x) = |x| show that ƒ’(2)=1

Given function is f(x) = |x|


LHD at x = 2:




RHD at x = 2:




As, LHD = RHD


Therefore, f(x) = |x| is differentiable at x = 2


Now f’(2) =


Therefore,


f’(2) = 1


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