Let A = {2, 3, 4, 5, …, 17, 18}. Let ‘≃’ be the equivalence relation on A × A, cartesian product of A with itself, defined by (a, b) ≃ (c, d) iff ad = bc. Then, the number of ordered pairs of the equivalence class of (3, 2) is
Let (3,2) ≃ (x,y)
⇒ 3y = 2x
This is possible in the cases:
x = 3, y = 2
x = 6, y = 4
x= 9, y =6
x=12, y = 3
x=15, y = 10
x=18,y=12
Hence total pairs are 6.