If f : R → R, g : R → R are given by f(x) = (x + 1)2 and g(x) = x2 + 1, then write the value of fog (–3).

Formula:-


(I)Let f : AB and g : BC be two functions.


Then, the composition of f andg, denoted by g o f, is defined as the function g o f : AC


given by g o f (x) = g (f (x))


Given:-


(i) f : R → R


(ii) g : R → R


(iii) f(x) = (x + 1)2


(iv) g(x) = x2 + 1


fog(-3)=f(g(-3))


fog(-3)=f((-3)2+1)


fog(-3)=f(10)


fog(-3)=(10+1)2


fog(-3)=121


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