Let f : R → R, g : R → R be two functions defined by f(x) = x2 + x + 1 and g(x) = 1 – x2. Write fog(–2).

Formula :- (I)Let f : AB and g : BC be two functions.


Then, the composition of f and g, denoted by g o f, is defined as the function g o f : AC


given by g o f (x) = g (f (x))


Given:-


(i)f : R → R


(ii)g : R → R


(iii) f(x) = x2 + x + 1


(iv)g(x) = 1 – x2


Fog(-2)=f(g(-2))


Fog(-2)=f(1-(-2)2)


Fog(-2)=f(-3)


Fog(-2)=(-3)2-3+1=7


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