Mark the correct alternative in each of the following: Let A = {x ϵ R : –1 ≤ x ≤ 1} = B and C = {x ϵ R : X ≥ 0} and let S = {(x, y) ϵ A × B : x 2 + y 2 = 1} and S 0 = {(x, y) ϵ A × C : x 2 + y 2 = 1} Then

Question

Philoid · Accepted Answer

Given that

A = {x ϵ R: –1 ≤ x ≤ 1} = B

C = {x ϵ R: X ≥ 0}

S = {(x, y) ϵ A × B: x² + y² = 1}

S₀ = {(x, y) ϵ A × C: x² + y² = 1}

x² + y² = 1

⇒ y² =1 - x²

∴ y ϵ B

Hence, S defines a function from A to B.

Mark the correct alternative in each of the following:Let A = {x ϵ R : –1 ≤ x ≤ 1} = B and C = {x ϵ R : X ≥ 0} and let S = {(x, y) ϵ A × B : x2 + y2 = 1} and S0 = {(x, y) ϵ A × C : x2 + y2 = 1} Then

Mark the correct alternative in each of the following:
Let A = {x ϵ R : –1 ≤ x ≤ 1} = B and C = {x ϵ R : X ≥ 0} and let S = {(x, y) ϵ A × B : x² + y² = 1} and S₀ = {(x, y) ϵ A × C : x² + y² = 1} Then