Mark the correct alternative in each of the following:
If f : A → B given by 3f(x) + 2–x = 4 is a bijection, then
Given that f: A → B given by 3f(x) + 2–x = 4 is a bijection.
3f(x) + 2–x = 4
⇒ 3f(x) = 4 - 2–x
⇒ 4 - 2–x ≥ 0
⇒ 4 ≥ 2–x
⇒ 2 ≥ -x
⇒ x ≥ -2
So, x ϵ (-2, ∞)
But, for x =0, f(x) = 1.
Hence, the correct option is none of these.