Mark the correct alternative in each of the following:
The function f : [0, ∞) → R given by f(x) is
Given that f: [0, ∞) → R where
Let f(x) = f(y)
⇒ xy + x = xy + y
⇒ x = y
So, f is one-one.
Now, y = f(x)
⇒ xy + y = x
⇒ y = x – xy
Here, y≠1 i.e. y ϵ R.
So, f is not onto.