Mark the correct alternative in each of the following:
The function f : R → R defined by f(x) = (x – 1) (x – 2) (x – 3) is
Given that function f : R → R where f(x) = (x – 1) (x – 2) (x – 3)
If f(x) = f(y)
Then
(x – 1) (x – 2) (x – 3) = (y – 1) (y – 2) (y – 3)
⇒ f(1) = f(2) = f(3) = 0
So, f is not one-one.
y = f(x)
∵ x ϵ R also y ϵ R so f is onto.