Mark the correct alternative in each of the following:

Let f : R –{n} R be a function defined by where m ≠ n. Then,


Given that f : R –{n} R where



Let f(x) = f(y)



(x-m)(y-n)=(x-n)(y-m)


xy – xn – my + mn = xy – xm – ny + mn


x = y


So, f is one-one.




y(x-n)=(x-m)


xy – ny = x – m


x(y-1) = ny – m



For y = 1 , no x is defined.


So, f is into.

1