Mark the correct alternative in each of the following:
Let f : R → R be a function defined by Then, f is
Given that f : R → R be a function where
Here, we can see that for negative as well as positive x we will get same value.
So, it is not one-one.
y = f(x)
⇒ y(x2 + 2) = (x2 – 8)
⇒ x2(y-1)=- 2y – 8
For y = 1 , no x is defined.
So, f is not onto.