Mark the correct alternative in each of the following:

Let [x] denote the greatest integer less than or equal to x. If f(x) = sin–1 x, g(x) = [x2] and then


Given that f(x) = sin–1 x, g(x) = [x2] and


a. goh(x) = g(2x)


goh(x) = [4x2]


fogoh(x) = f([4x2])


fogoh(x) = sin–1 [4x2]


Hence, given option is incorrect.


b. Similarly, this option is also incorrect.


c. fog(x) = f([x2])


fog(x) = sin–1 [x2]


hofog(x) = h(sin–1 [x2])


hofog(x) = 2(sin–1 [x2])


gof(x) = g(sin–1 x)


gof(x) = [(sin–1 x)2]


hogof(x) = h([(sin–1 x)2])


hogof(x) = 2[(sin–1 x)2]


Hence, hogof(x) ≠ hofog(x)

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