For the binary operation multiplication modulo 5(×5) defined on the set S = {1, 2, 3, 4}. Write the value of (3 ×5 4–1)–1.
From the definition of multiplication modulo
a*b = (m is the base of the modulo)
Here the base is 5 and the set is S = {1,2,3,4}
So, we can make a composition table as :-
The identity element is 1.
The inverse element of 4 is 4 itself.
∴ (3 4-1)-1 = (3
1) -1 = 3-1 = 2.