RD Sharma - Mathematics (Volume 1)

Book: RD Sharma - Mathematics (Volume 1)

Chapter: 4. Inverse Trigonometric Functions

Subject: Maths - Class 12th

Q. No. 32 of MCQ

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32

Choose the correct answer

The value of is equal to


We need to find the value of sin (2(tan-1 0.75)).

We can re-write the equation,


sin (2(tan-1 0.75)) = sin (2 tan-1 0.75)


Using the property of inverse trigonometry,



Replace x by 0.75.



So,


sin (2(tan-1 0.75)) = sin (2 tan-1 0.75)





⇒ sin (2(tan-1 0.75)) = sin (sin-1 0.96)


Using the property of inverse trigonometry,


sin(sin-1 A) = A


⇒ sin (2(tan-1 0.75)) = 0.96

Chapter Exercises

Exercise 4.1
Exercise 4.2
Exercise 4.3
Exercise 4.4
Exercise 4.5
Exercise 4.6
Exercise 4.7
Exercise 4.8
Exercise 4.9
Exercise 4.10
Exercise 4.11
Exercise 4.12
Exercise 4.13
Exercise 4.14
Very short answer
MCQ

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