If the mean and variance of a binomial distribution are 4 and 3 respectively, find the probability of no-success.

Given:

Mean=4

Variance=3

P(x=0)=?

P(x=r)= ^{n}C_{r} p^{r} q^{n-r}

p(x=0)= 11q^{n}

4(1-p)=3

=q

np=4

n=16