If the mean and variance of a binomial distribution are 4 and 3 respectively, find the probability of no-success.
Given:
Mean=4
Variance=3
P(x=0)=?
P(x=r)= nCr pr qn-r
p(x=0)= 1
1
qn
4(1-p)=3
=q
np=4
n=16
1
If the mean and variance of a binomial distribution are 4 and 3 respectively, find the probability of no-success.
Given:
Mean=4
Variance=3
P(x=0)=?
P(x=r)= nCr pr qn-r
p(x=0)= 11qn
4(1-p)=3
=q
np=4
n=16