Mark the correct alternative in the following:

If the mean and variance of a binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than 1 is

Given:

Mean= 2

Variance=1

P(x>1)=?

P(x>1)=1-p(x1)

= 1-[p(x=0)+p(x=1)]

=1-[ 11q^{n} +npq^{n-1}]

2(1-p)=1

=q

np=2

n=4

1