Mark the correct alternative in the following:

The mean and variance of a binomial distribution are 4 and 3 respectively, then the probability of getting exactly six successes in this distribution, is

Given:

Mean=4

Variance=3

P(x=6)=?

P(x=r)= ^{n}C_{r} p^{r} q^{n-r}

4(1-p)=3

=q

np=4

n=16

P(x=r)= ^{n}C_{r} p^{r} q^{n-r}

P(x=6)= ^{16}C_{6}

1