Mark the correct alternative in the following:

The mean and variance of a binomial distribution are 4 and 3 respectively, then the probability of getting exactly six successes in this distribution, is


Given:


Mean=4


Variance=3


P(x=6)=?


P(x=r)= nCr pr qn-r


4(1-p)=3



=q



np=4


n=16


P(x=r)= nCr pr qn-r


P(x=6)= 16C6

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