Mark the correct alternative in the following:
The mean and variance of a binomial distribution are 4 and 3 respectively, then the probability of getting exactly six successes in this distribution, is
Given:
Mean=4
Variance=3
P(x=6)=?
P(x=r)= nCr pr qn-r
4(1-p)=3
=q
np=4
n=16
P(x=r)= nCr pr qn-r
P(x=6)= 16C6