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Mark the correct alternative in the following:
For a binomial variate X, if n = 3 and P (X = 1) = 8 P(X = 3), then p =
Given:
n=3
P (X = 1) = 8 P (X = 3)
P =?
P(x=r)= nCr pr qn-r
P(x=1)= nC1 p1 qn-1
=3p
q2 (1)
P(x=3)= 3C3 p3 q0
= p3(2)
Put values in the equations ,we have:
3p
q2 =8 p3
3 (1-p)2 = 8p2
3+3p2-6p = 6p2
5p2+6p-3=0