Mark the correct alternative in the following:

For a binomial variate X, if n = 3 and P (X = 1) = 8 P(X = 3), then p =


Given:


n=3


P (X = 1) = 8 P (X = 3)


P =?


P(x=r)= nCr pr qn-r


P(x=1)= nC1 p1 qn-1


=3pq2 (1)


P(x=3)= 3C3 p3 q0


= p3(2)


Put values in the equations ,we have:


3pq2 =8 p3


3 (1-p)2 = 8p2


3+3p2-6p = 6p2


5p2+6p-3=0





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