A random variable X takes the values 0, 1, 2, 3 and its mean is 1.3. If P (X =3) = 2P (X = 1) and P(X = 2) = 0.3, then P(X = 0) is
Let the value P(X=0) be x and the value of P(X=1) be A
GIVEN- P(X=3) =2P(X=1)
=2(A) =2A
P(X=2) =0.3
So, The Probability distribution of X is
Mean of E(X) =1.3
⇒ (0×x)+(1×A)+(2×0.3)+(3×2A)=1.3
⇒ A+0.6+6A=1.3
⇒ 7A+0.6=1.3
⇒ 7A=0.7
⇒ A=0.1
By putting the value of A in probability distribution, we get
We Know that
Therefore,
⇒ x+0.1+0.3+0.2=1
x=1-0.6
x=0.4