A random variable X takes the values 0, 1, 2, 3 and its mean is 1.3. If P (X =3) = 2P (X = 1) and P(X = 2) = 0.3, then P(X = 0) is

Let the value P(X=0) be x and the value of P(X=1) be A


GIVEN- P(X=3) =2P(X=1)


=2(A) =2A


P(X=2) =0.3


So, The Probability distribution of X is



Mean of E(X) =1.3



(0×x)+(1×A)+(2×0.3)+(3×2A)=1.3


A+0.6+6A=1.3


7A+0.6=1.3


7A=0.7



A=0.1


By putting the value of A in probability distribution, we get



We Know that



Therefore,


x+0.1+0.3+0.2=1


x=1-0.6


x=0.4

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