For the following probability distribution:
The value of E(X) is
The probability distribution of X is:
We Know that
Therefore,
(-4×0.1)+(-3×0.2)+(-2×0.3)+(-1×0.2)+(0×0.2)
⇒ -0.4-0.6-0.6-0.2
1
For the following probability distribution:
The value of E(X) is
The probability distribution of X is:
We Know that
Therefore,
(-4×0.1)+(-3×0.2)+(-2×0.3)+(-1×0.2)+(0×0.2)
⇒ -0.4-0.6-0.6-0.2