Write the plane in normal form.

The plane is given as, .


We can write the equation of the plane in general form as,


2x + 3y - 6z - 14=0 …………… (1)



Now, to get the normal form of a plane given in general form as, Ax + By + Cz + D=0 where …… (2), we have to divide the equation (1) by , where is the normal vector given as,


Now,






Comparing equation (1) with equation (2), we get, D= - 14





=2


[where p is the distance between the plane and the origin]


Normal form of the equation is given as,



Here, normal form of the given plane is,




1