Write the equation of a plane which is at a distance of units from the origin and the normal to which is equally inclined to coordinate axes.

Given, the plane is at a distance of units form the origin and the normal to the plane is equally inclined with the co - ordinates axis, so, its direction cosines are



We know, for a plane having direction cosines as l, m and n, and p be the distance of the plane from the origin, the equation of the plane is given as, lx + my + nz=p


So, in this problem, the equation of the required equation of the plane is given by,




=15


Hence, the equation of the required plane which is at a distance of units from the origin and the normal to which is equally inclined to co - ordinate axes is


x + y + z=15.


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