Mark the correct alternative in the following:

If a plane passes through the point (1, 1, 1) and is perpendicular to the line then its perpendicular distance from the origin is


Let, the equation of the plane be, Ax + By + Cz + D=0, as the plane is perpendicular to, so, we have,


A=3, B=0 and C=4


As the plane passes through (1, 1, 1) we have, (A×1) + (B×1) + (C×1) + D=0


A + B + C + D=0


3 + 0 + 4 + D=0


D= - 7


So, the equation of the plane becomes, 3x + 4z - 7=0


Now, the perpendicular distance of the plane from the origin is








Hence, the perpendicular distance from the origin to the plane is units.

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