The equation of the normal to the curve y = x (2 – x) at the point (2, 0) is
Given that y = x (2 – x)
⇒ y = 2x – x2
Slope of the tangent
Slope at (2, 0) = 2 – 4 = -2
Equation of normal:
⇒2y=x-2
⇒ x – 2y – 2 = 0
Hence option A is correct.
1
The equation of the normal to the curve y = x (2 – x) at the point (2, 0) is
Given that y = x (2 – x)
⇒ y = 2x – x2
Slope of the tangent
Slope at (2, 0) = 2 – 4 = -2
Equation of normal:
⇒2y=x-2
⇒ x – 2y – 2 = 0
Hence option A is correct.