The point on the curve y = x 2 – 3x + 2 where tangent is perpendicular to y = x is

Question

Philoid · Accepted Answer

Given that the curve y = x² – 3x + 2 where tangent is perpendicular to y = x

Differentiating both w.r.t. x,

∵ the point lies on the curve and line both

Slope of the tangent = -1

⇒ 2x – 3 = -1

⇒ x = 1

And y = 1-3+2

⇒ y =0

So, the required point is (1, 0).