The slope of the tangent to the curve x = t 2 + 3t – 8, y = 2t 2 – 2t – 5 at point (2, –1) is

Question

Philoid · Accepted Answer

Given that x = t² + 3t – 8, y = 2t² – 2t – 5

Differentiating both the sides,

The given point is (2, -1)

2 = t² + 3t – 8, -1 = 2t² – 2t – 5

On solving we get,

t = 2 or -5 and t = 2 or -1

∵ t =2 is the common solution

So,