The slope of the tangent to the curve x = 3t 2 + 1, y = t 3 – 1 at x = 1 is

Question

Philoid · Accepted Answer

Given that x = 3t² + 1, y = t³ – 1

For x = 1,

3t² + 1=1

⇒ 3t² = 0

⇒ t =0

Now, differentiating both the equations w.r.t. t, we get

⇒Slope of the curve:

For t =0,

Slope of the curve =0

Hence, option B is correct.