The line y = mx + 1 is a tangent to the curve y2 = 4x, if the value of m is
It is given that the line y = mx + 1 is a tangent to the curve y2 = 4x.
Slope of the line = m
Slope of the curve
Differentiating the curve we get
∵ The given line is a tangent to the curve so the point passes through both line and curve.
⇒ 2 – m =1
⇒ m = 1
Hence, the correct option is A.