Matrix is given to be symmetric, find the values of a and b.
We are given that,
is symmetric matrix.
We need to find the values of a and b.
We must understand what symmetric matrix is.
A symmetric matrix is a square matrix that is equal to its transpose.
A symmetric matrix ⬄ A = AT
This means, we need to find the transpose of matrix A.
Let us take transpose of the matrix A.
We know that, the transpose of a matrix is a new matrix whose rows are the columns of the original.
We have,
1st row of matrix A = (0 2b -2)
2nd row of matrix A = (3 1 3)
3rd row of matrix A = (3a 3 -1)
For matrix AT, it will become
1st column of AT = 1st row of A = (0 2b -2)
2nd column of AT = 2nd row of A = (3 1 3)
3rd column of AT = 3rd row of A = (3a 3 -1)
Now, as A = AT.
Substituting the matrices A and AT, we get
We know by the property of matrices,
This implies,
a11 = b11, a12 = b12, a21 = b21 and a22 = b22
Applying this property, we can write
2b = 3 …(i)
-2 = 3a …(ii)
3 = 2b
3a = -2
We can find a and b from equations (i) and (ii).
From equation (i),
2b = 3
From equation (ii),
-2 = 3a
Thus, we get and
.